In the one of the previous sections we showed an example of how to create a linked list in Python. Let’s test create the same list as in the previous section and print out the values of each node:ġ5 How to insert a node at the end of a linked list in Python It will be added as a method of the LinkedList() class: In this section we will implement a method print_llist() for traversing a linked list and printing values of each node for the LinkedList() class.
In order to create a sequence of nodes, we will set each reference link to point to the next node:Īnd now we have successfully created a linked list with three nodes which should look like this: Recall that each node has a reference link set to NULL. This will create a linked list with one node (which will be the head node). To start adding nodes to a linked list we want the first_node we created to be the head node of the linked list: When initialized, a linked list should only have the head node set to NULL, in order to start an empty linked list: The next step is to create a structure for a linked list (as its own class). Let’s go ahead and create a few more individual nodes:Īt this point we have three nodes which are not connected to each other: first_node, second_node, third_node.
To test the code, let’s create a node that will have a value equal to 5, and print out the value and the pointer to next node:Īs we expected, the values stored is 5 and reference link to next node is None. When initialized, a node should take some data to use as the value, as well as have a default pointer to next node set to None, which will be changed as we add more nodes together to form a sequence. The first step to creating a linked list is to create a structure of a node (as its own class). We already know that a linked list is a sequence made from nodes.
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